-HCl, H2SO4, HClO4
-Strong Bases (SB) dissociate to produce OH- ions
-NaOH, Ba(OH)2, LiOH
-When a SA and SB mix they form water and an ionic salt
-Total volume changes
pH and pOH
-pH is a measure of the hydrogen ions present in a solution
pH = -log[H+]
-pOH is a measure of the hydroxide ions present in a solution
pOH = -log[OH-]
Example
-100mL of 0.250M HCl is added to 100mL of 0.250M LiOH
-Determine the mass of water produced.
HCl + LiOH ----> HOH + LiCl
0.250mol/L x .100L x 1/1 x 18g/1mol = 0.45g
-Determine the mass of the salt produced
.45g x 1mol/18g x 1/1 x 42.4g/1mol =1.06g
Example
-100mL of .250M HCl is added to 200mL of .150M LiOH
-Determine the L.R.
0.250mol/L x .100L = .0250mol
.150mol/L x .200L x 1/1 = .0300mol
L.R. HCl
-How much LiOH is left over when the reaction is complete?
0.206L x 0.150mol/L = .0300mol LiOH started with
0.0250mol x 1/1 = .0250mol LiOH used
.0300mol - .0250mol = .0050mol LiOH left
-Determine [LiOH] after the reaction is complete
0.0050mol x 1/.300L = 0.0167 M = [LiOH]
-Find the pOH of the final solution
LiOH ----> Li+ + OH-
.0167M .0167M .0167M
pOH = -log[OH-]
pOH= -log[0.0167M]
= 1.78
-T.H
No comments:
Post a Comment